Hi, I have to differentiate z=w^3/2(w+ce^w) does anyone know how to do this? Thank you in advance
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You could use the product rule, have you tried that?
Or the Quotient Rule... $\displaystyle \displaystyle \begin{align*} \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{v\,\frac{du}{dx} - u\,\frac{dv}{dx}}{v^2} \end{align*} $
Originally Posted by angelamonique Hi, I have to differentiate z=w^3/2(w+ce^w) does anyone know how to do this? Thank you in advance I am confused by your use of parentheses. Do you mean z = (w^3/2)(w + c*e^(w)) OR do you mean z = (w^3)/(2(w + c*e^(w))? See the difference?
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