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Math Help - Limit

  1. #1
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    Limit

    Hey guys.

    Can I please have some help with this limit over here

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    Thanks a lot.
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  2. #2
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    Re: Limit

    BTW

    I cant use l'H˘pital's rule.

    I'm trying to help someone how haven't learned how to Derivative yet.

    Thanks a lot.
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  3. #3
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    Re: Limit

    Quote Originally Posted by asi123 View Post
    BTW

    I cant use l'H˘pital's rule.

    I'm trying to help someone how haven't learned how to Derivative yet.

    Thanks a lot.
    You should start by rationalising the numerator, then dividing top and bottom by the highest power of x.
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  4. #4
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    Re: Limit

    Well, This is what I got.

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    I cant put zero into that, it doesn't give me much, right?

    Thanks a lot.
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  5. #5
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    Re: Limit

    Quote Originally Posted by asi123 View Post
    Hey guys.

    Can I please have some help with this limit over here

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    Thanks a lot.
    \lim_{x \to \0}\frac{\sqrt{x^2+1}-1}{\sqrt{x^2+16}-4} \cdot \frac{(\sqrt{x^2+1}+1)(\sqrt{x^2+16}+4)}{(\sqrt{x^  2+1}+1)(\sqrt{x^2+16}+4)}=

    =\lim_{x \to \0}\frac{x^2 \cdot (\sqrt{x^2+16}+4)}{x^2 \cdot (\sqrt{x^2+1}+1)}
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  6. #6
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    Re: Limit

    Thanks a lot.
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