# Math Help - how is this equal to each other?

1. ## how is this equal to each other?

How is $\frac {3x^3}{x^3+1} = \frac {3}{1+\frac {1}{x^3}}$?

If this is not true the initial equation I used was $\frac {3x^2}{x^3+1}$ ÷ $\frac {1}{x}}$

2. ## Re: how is this equal to each other?

Originally Posted by Barthayn
How is $\frac {3x^3}{x^3+1} = \frac {3}{1+\frac {1}{x^3}}$?

If this is not true the initial equation I used was $\frac {3x^2}{x^3+1}$ ÷ $\frac {1}{x}}$
That is basic grade school algebra.
If you have trouble with that, you have no reason to be doing calculus.