How is $\displaystyle \frac {3x^3}{x^3+1} = \frac {3}{1+\frac {1}{x^3}}$? If this is not true the initial equation I used was $\displaystyle \frac {3x^2}{x^3+1}$ ÷ $\displaystyle \frac {1}{x}}$
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Originally Posted by Barthayn How is $\displaystyle \frac {3x^3}{x^3+1} = \frac {3}{1+\frac {1}{x^3}}$? If this is not true the initial equation I used was $\displaystyle \frac {3x^2}{x^3+1}$ ÷ $\displaystyle \frac {1}{x}}$ That is basic grade school algebra. If you have trouble with that, you have no reason to be doing calculus.
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