Square root of complex number

I'm at a loss how to go about solving equations like the one below, where there are j terms under the square root sign.

http://i43.tinypic.com/fx84yr.png

I've tried getting the complex conjugate of what's under the square root sign but i'll still have a j term.

I'm convinced it's a straightforward process and that I'm missing some simple trick.

Clues/Hints/Ideas/Whatever welcome!

Re: Square root of complex number

Re: Square root of complex number

Yes I got it down that far but wondering how to solve that fraction when it's under a square root and then convert it to an polar exponential like the picture in my first post. Any ideas?

By the way, we're solving for Eta, the intrinsic impedance of a medium that has a magnetic field passing through it.

Re: Square root of complex number

Quote:

Originally Posted by

**piglet** Yes I got it down that far but wondering how to solve that fraction when it's under a square root and then convert it to an polar exponential like the picture in my first post. Any ideas?

By the way, we're solving for Eta, the intrinsic impedance of a medium that has a magnetic field passing through it.

You multiply the top and bottom of the fraction by the complex conjugate of the denominator, which reduces the fraction to something of the form

Now convert that into polar form and the square root is easy-peasea from there.

CB