Solving this double integral.
I want to solve this.
I'm not sure what to do. I used integration by parts and I got stuck. I tried changing the order as well and i think it made it worse.
u = 1/y
du = -1/y^2
dv = cos y
v = sin y
so i get
sin y/y + int (cos y)/y^2 from integration by parts.
If i change the order, I get the bounds as 0 to 1 for the outer integral and y to 1 for the inner integral and switching the dx and dy. That gives me
(cos y)/y - cos y for the inner integral.
So I'm not sure what to do now...
Re: Solving this double integral.