a(n) = (2^(n-1)) / ((2^n)-1)

with n --> infinite.

thank you :)

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- Nov 27th 2011, 12:51 PMnappysnakeHow would you go about calculating this simple limit?
a(n) = (2^(n-1)) / ((2^n)-1)

with n --> infinite.

thank you :) - Nov 27th 2011, 01:04 PMskeeterRe: How would you about calculating this simple limit?
- Nov 27th 2011, 01:11 PMnappysnakeRe: How would you about calculating this simple limit?
thank you skeeter for letting me come to a crucial realization, it was very clear :)