What is Laplace Inverse of

exp(-s) / (s+1)

and also for

$\displaystyle exp(-s) /[ (s+1)(s+1)]$

in second term, at denominator we are having square of (s+1)

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- Nov 24th 2011, 04:11 PMmoonnightingaleLaplace Inverse
What is Laplace Inverse of

**exp(-s) / (s+1)**

and also for

$\displaystyle exp(-s) /[ (s+1)(s+1)]$

in second term, at denominator we are having square of (s+1) - Nov 24th 2011, 04:50 PMProve ItRe: Need help with Laplace Inverse