Hello, NeoSonata!
Why do you think your answer is wrong?
lim x->1 (2-x)^(tan(pi(x)/2))
I plugged it in and got 1^infinity (indeterminate form) because tan (pi(1)/2) is 1/0 or infinity
so:
lny = (tan(pi(x)/2)) * ln(2-x)
= ln(2-x) / cot (pi(x)/2)
L'H = (-1/2-x) / csc^2(pi(x)/2) ( -pi/2)
= -1/ -pi/2
= 2/pi
lim x->1 y = e^(2/pi)
?
Where did I go wrong?
Thanks
You must have entered it into Wolfram wrongly, since the limit is .
limit of [(2-x)^(Tan[Pi * x / 2])] as x to 1 - Wolfram|Alpha