How would I find the maclaurin series for the following function: $\displaystyle f(x) = \frac{3}{(1-x)^2}$.

The first, second, and third derivatives are:$\displaystyle \frac{6}{(1-x)^3}, \frac{18}{(1-x)^4}, \frac{72}{(1-x)^5}$.

$\displaystyle f(x)=\Sigma \frac{f^{(n)}(0)}{n!}x^n = 3 + 6x +\frac{18}{2!}x^2 + \frac{72}{3!}x^3 + ...$.

Here's where I'm stuck.

Any help would be greatly appreciated.