$\displaystyle \lim_{x\to\infty}\frac{sin(x^2+5)}{x^2}$

I know that $\displaystyle sin(x^2+5)$ will oscillate between 1 and -1 and that $\displaystyle \lim_{x\to\infty}\frac{1}{x^2}$ = 0

Is this a case for using the squeeze theorem? How do I write out the answer correctly? Or is it just the limit of of the $\displaystyle \frac{1}{x^2}$ function = 0 and the limit of the product of two functions is the product of the limits and 0*anything = 0 ?

Thanks.