Swimming pool is 10m long, 6m wide, depth is 1m at one end and 1.5m at the other end.
It's being filled with water at a rate of 50,000 cm^3 / minute.
After 225 minutes after the hose is turned on, the water is rising at a rate of _____cm per second.
Here's what I did:
dv/dt = 833 1/3 cm^3 / second
dv/dt = wl(dD/dt)
wl = 60,000cm
so dD/dt = dv/dt / 60,000
dD/dt = (833 1/3) / 60,000
dD/dt = 0.014 cm/sec for the answer.
Does the 225 minutes even come into play? I'm thinking it would since the depth isn't constant?