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**stefanhinote** Swimming pool is 10m long, 6m wide, depth is 1m at one end and 1.5m at the other end.

It's being filled with water at a rate of 50,000 cm^3 / minute.

After 225 minutes after the hose is turned on, the water is rising at a rate of _____cm per second.

Here's what I did:

dv/dt = 833 1/3 cm^3 / second

dv/dt = wl(dD/dt)

wl = 60,000cm

so dD/dt = dv/dt / 60,000

dD/dt = (833 1/3) / 60,000

dD/dt = 0.014 cm/sec for the answer.

Does the 225 minutes even come into play? I'm thinking it would since the depth isn't constant?