Suppose routine integration by parts yields:

Where does not necessarily have an antiderivate.

Then is it correct to assume that ?

Thanks for any help.

James

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- Nov 21st 2011, 06:40 AMjames121515Integration by parts
Suppose routine integration by parts yields:

Where does not necessarily have an antiderivate.

Then is it correct to assume that ?

Thanks for any help.

James - Nov 22nd 2011, 04:21 PMMonroeYoderRe: Integration by parts
yeah all you've done is plugged in the limits for your g, you're good