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Math Help - Finding rate of change of volume in a cylinder.

  1. #1
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    Finding rate of change of volume in a cylinder.

    I've attached a picture to make things easier to read.

    Finding rate of change of volume in a cylinder.-help.png

    The rate I got sounds absurd, and it doesn't take the "3 seconds" into consideration.

    Did I do something wrong? Any help would be greatly appreciated.
    Last edited by stefanhinote; November 20th 2011 at 01:10 PM.
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  2. #2
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    Re: Finding rate of change of volume in a cylinder.

    your calculation of dV/dt is correct, except for your units ... the time does not matter since dV/dt = k(dh/dt)
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    Re: Finding rate of change of volume in a cylinder.

    Quote Originally Posted by skeeter View Post
    your calculation of dV/dt is correct, except for your units ... the time does not matter since dV/dt = k(dh/dt)

    mm^3 / sec since it's volume, my bad.

    Thank you!
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  4. #4
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    Re: Finding rate of change of volume in a cylinder.

    your answer is fine except that the units are mm^3 / sec

    im not sure why 3 seconds is mentioned in the question to be honest, as ther ate of change will be constant provided the candy continues to move at 7mm/sec.

    edit: i was too slow :P
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  5. #5
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    Re: Finding rate of change of volume in a cylinder.

    Quote Originally Posted by SpringFan25 View Post
    your answer is fine except that the units are mm^3 / sec

    im not sure why 3 seconds is mentioned in the question to be honest, as ther ate of change will be constant provided the candy continues to move at 7mm/sec.
    I wondered the same, I guess it's just added to "throw off" people.
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