I would like to know if the Taylor series for the sine function,

sin(x) = x - x^3/3! + x^5/5! -...

is convergent if the argument of the function, x , is expressed in degrees instead of radians.

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- November 20th 2011, 06:22 AMjfpejiConvergence of the Taylor series for the sine function
I would like to know if the Taylor series for the sine function,

sin(x) = x - x^3/3! + x^5/5! -...

is convergent if the argument of the function, x , is expressed in degrees instead of radians. - November 20th 2011, 07:08 AMTheChazRe: Convergence of the Taylor series for the sine function
Well wouldn't that imply that one degree equals one radian?!?

- November 20th 2011, 07:58 AMCaptainBlackRe: Convergence of the Taylor series for the sine function
- November 20th 2011, 08:28 AMjfpejiRe: Convergence of the Taylor series for the sine function
Ok. You are right. Thank you for your answer.

- November 20th 2011, 08:42 AMjfpejiRe: Convergence of the Taylor series for the sine function
What is that different series which converges to the sin, where the argument is in degrees, that you mention?

- November 20th 2011, 11:26 AMCaptainBlackRe: Convergence of the Taylor series for the sine function
- November 20th 2011, 11:36 AMjfpejiRe: Convergence of the Taylor series for the sine function
Ok. You are right. Thank you for your answer.