How would I solve the integral (9-y^2)^(1/2) aka : sqrt(9-y^2)
Follow Math Help Forum on Facebook and Google+
You could use an appropriate substitution. At a guess, I'd consider letting $\displaystyle y=3sin(x)$
$\displaystyle \int \sqrt{a^2-x^2}dx=\frac{1}{2}[x\sqrt{a^2-x^2}+a^2\sin^{-1}(\frac{x}{a})]+K$
View Tag Cloud