How would I solve the integral (9-y^2)^(1/2)

aka : sqrt(9-y^2)

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- Nov 18th 2011, 07:03 PMCerbyIntegral of (9-y^2)^(1/2)
How would I solve the integral (9-y^2)^(1/2)

aka : sqrt(9-y^2) - Nov 18th 2011, 07:12 PMQuackyRe: Integral of (9-y^2)^(1/2)
You could use an appropriate substitution.

At a guess, I'd consider letting $\displaystyle y=3sin(x)$ - Nov 19th 2011, 12:38 AMsbhatnagarRe: Integral of (9-y^2)^(1/2)
$\displaystyle \int \sqrt{a^2-x^2}dx=\frac{1}{2}[x\sqrt{a^2-x^2}+a^2\sin^{-1}(\frac{x}{a})]+K$