Thread: Chain Rule

Let f(3) = 1, g(2) = 3, f'(3) = 4, g'(2) = 5. If h(x) = f(g(x)), find h'(2).


My professor got 20 for this. Why would you ignore g(2)?

Wouldn't it be 4*3 * 5?
Because the chain rule is f'(g(x)) * g'(x)

Originally Posted by habibixox

Let f(3) = 1, g(2) = 3, f'(3) = 4, g'(2) = 5. If h(x) = f(g(x)), find h'(2).


My professor got 20 for this. Why would you ignore g(2)?

Wouldn't it be 4*3 * 5?
Because the chain rule is f'(g(x)) * g'(x)

note that is substituted into the term ...