Geometric interpretation: the integrand function is . Taking squares we see that represents a circle centered and radius . So the integral is half of the area of the corresponding disk, that is .
P.S. Prove It: surely you have a computation mistake, the integral must be positive.
You are correct that should integrate to , but that sign error doesn't make any difference since it goes to 0 from substituting both terminals anyway.
I have found what my mistake is. Since , that means when I took the square root, I should have done , not to get the positive value.