find the critical points of on I have a question when i get to this part. When I set to zero, do I break into part then mutlipy the inverses of both sides? 10sin = 0 and cosx=0
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Easier way (I think) Recall your double-angle formula We have: This gives us that immediately, where n is an integer.
Originally Posted by delgeezee find the critical points of on I have a question when i get to this part. When I set to zero, do I break into part then mutlipy the inverses of both sides? 10sin = 0 and cosx=0 You don't MULTIPLY the inverse on both sides, you just take the inverse... But what you are saying is correct in essentials, so you now just need to find where sin(x) = 0 and cos(x) = 0.
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