1. ## another volume integral

Hi everyone,

The graphs cross at (0,0) and at (1,1)

I then would take the integral from 0 to 1 pie(sq. x squared)-pie(x squared) dx, which is 1/6pie. Is that correct???????

Thank you very much

2. Originally Posted by chocolatelover
Hi everyone,

Please note: $\pi$ is spelled "pi."
Your question makes no sense. Are you asking for the volume generated by rotating the area between $y = x$ and $y = \sqrt{x}$ rotated about the line x = 2? Please be more specific.