Hi everyone,

Could someone please help me with this? I'm trying to find the volume under the curve: y=x, sqare root x; about x=2

The graphs cross at (0,0) and at (1,1)

I then would take the integral from 0 to 1 pie(sq. x squared)-pie(x squared) dx, which is 1/6pie. Is that correct???????:confused:

Thank you very much