(letting u = 1/n)

two comments:

1. we can take the limit inside the ln function, since ln is continuous

2. the number e is often DEFINED as:

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- Nov 10th 2011, 10:07 PM #1

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## why is it that ln(1+u)^(1/u)=1

why is it that as the limit of u approaches zero of ln(u+1)^(1/u)=1? I am trying to figure this out because I want to see the proof of the derivative of lnx = 1/x. I know that ln(u+1)^(1/u)=1 and when I plug in digits in my calculator I see it to be true, however, I cannot see it algebraically why it is true. I cannot see it because I see ln(1)^1/0. To me this is not possible.

- Nov 10th 2011, 11:04 PM #2

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