Hi everyone,
Could someone please help me with this interval?
Find the area under the curve:
4x+y squared=12
y=x
(-6,-6) (2,2)
I solved for x and got -1/4y squared+3
I then solved the integral -6 to 2 -1/4y squared+3-ydy
Once I plugged in my values I got a negative value.
5/3-18+6+1
but it can't be a negative area
Could someone please help me with this?
Thank you very much