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Math Help - volume integral

  1. #1
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    Exclamation volume integral

    Hi everyone,

    Could someone please help me with this interval?

    Find the area under the curve:

    4x+y squared=12
    y=x
    (-6,-6) (2,2)

    I solved for x and got -1/4y squared+3

    I then solved the integral -6 to 2 -1/4y squared+3-ydy

    Once I plugged in my values I got a negative value.

    5/3-18+6+1

    but it can't be a negative area

    Could someone please help me with this?

    Thank you very much
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  2. #2
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    Quote Originally Posted by chocolatelover View Post
    Hi everyone,

    Could someone please help me with this interval?

    Find the area under the curve:

    4x+y squared=12
    y=x
    (-6,-6) (2,2)

    I solved for x and got -1/4y squared+3

    I then solved the integral -6 to 2 -1/4y squared+3-ydy

    Once I plugged in my values I got a negative value.

    5/3-18+6+1

    but it can't be a negative area

    Could someone please help me with this?

    Thank you very much
    As I mentioned in my other post, what does
    "Find the area under the curve:

    4x+y squared=12
    y=x
    (-6,-6) (2,2) "
    mean??

    Are you again trying to find the area between two curves?

    -Dan
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