Hi everyone,

Could someone please help me with this interval?

Find the area under the curve:

4x+y squared=12

y=x

(-6,-6) (2,2)

I solved for x and got -1/4y squared+3

I then solved the integral -6 to 2 -1/4y squared+3-ydy

Once I plugged in my values I got a negative value.

5/3-18+6+1

but it can't be a negative area

Could someone please help me with this?

Thank you very much