f(x)=(x^2)(√(1-x^2))

f'(x)=(2x)(√(1-x^2))+(x^2)(1/2)(√(1-x^2))^-1)(-2x)

f'(x)=(2x)((1-x^2)^1/2)+(x^2)(1/2)(√(1-x^2)^-1)(-2x)

f'(x)=√(4x^2-4x^4)+(1/2)(-2x^3)(1/(√(1-x^2))

umm i'm lost, i probably didn't even get the above right (sorry the format sucks pretty bad)

never mind i found a picture