Thread: How to take the derivative of ln(lnx)?

How do you take the derivative of ln(lnx)?

This is where I go with it then I get confuse:

y=ln(lnx)
e^y=lnx.

From here I get lost. Everything I try does not work.

now, let

thanks I got it. It is (x ln(x))^-1. However, I do not understand why 1 over u?

Originally Posted by Barthayn

How do you take the derivative of ln(lnx)?

This is where I go with it then I get confuse:

y=ln(lnx)
e^y=lnx.

From here I get lost. Everything I try does not work.

Alternatively, you can just do implicit differentiation from there.







And you can see how this simplifies.