Pretty sure I have every part of this problem solved but my final answer concerns me as it seems a little high.
and for t>3
I should find the maximum altitude and time in which it gets there. My answer is 56s and 18565.18meters.
initial velocity ( is 366.4m/s)
initial position ( ) is 0
after taking integral of v(t)
= position fxn until 3 seconds.
after 3 seconds of burn
=position fxn after 3s initial burn.
Is it me or is that pretty dang high?