I guess I don't need to add the two x positions since the second one already has it in there. So 17087.98meters.
Pretty sure I have every part of this problem solved but my final answer concerns me as it seems a little high.
for 0<=t<=3
and for t>3
I should find the maximum altitude and time in which it gets there. My answer is 56s and 18565.18meters.
**additional info**
initial velocity ( is 366.4m/s)
initial position ( ) is 0
after taking integral of v(t)
**
= position fxn until 3 seconds.
after 3 seconds of burn
=position fxn after 3s initial burn.
at t=56.2145s
where t=56.2145s
17087.98+1477.2=18565.18meters
Is it me or is that pretty dang high?
for 0<=t<=3
and for t>3
So,
initial velocity ( is 366.4m/s)
initial position ( ) is 0
after taking integral of v(t)
Then, at 3 seconds:
and
so after 3 seconds
Finally:
at t=53.23seconds
then
So, it reaches a height of 15479.02m after flying for 53.23s. Still seems high to me...