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Math Help - Intergrals

  1. #1
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    Intergrals

    I am a bit stuck on this:
    (note: | = intergration symbol)

    2|6-3|6

    Now i think im right at that point. Not sure what to do from there?
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  2. #2
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    I don't get very well what you want.

    Use some of LaTeX.

    See the LaTeX Help forum.
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  3. #3
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    <br /> <br />
\left[ 2\int_3^5 6\right] - \left[ 3\int_3^5 6\right]<br /> <br />

    does that make more sense?
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  4. #4
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    Yeah a lot.

    It's very easy, since

    \int dx=x+k, then \int_a^b dx=b-a

    Does that make sense?
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  5. #5
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    wait so i say 5-3? what about the 6 and 3 and 2?
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  6. #6
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    Quote Originally Posted by taurus View Post
    wait so i say 5-3? what about the 6 and 3 and 2?
    2\int_3^5 6 - 3\int_3^5 6

    You're integrating with respect to what?

    We'll assume dx.

    Thus, 2\cdot [6(5) - 6(3)] - 3\cdot [6(5)-6(3)] = (2\cdot 12) - (3\cdot 12) = 24 - 36 = -12
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  7. #7
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    wait i think i got the question wrong, suppose we have:
    \int_3^5 f(x) dx = 6, \int_3^6 f(x) dx = 5, \int_3^5 g(x) dx = 6

    now it asks to find the value of the following integrals:
    \int_3^5 2f(x) -3 g(x) dx =
    ??
    ?? any ideas
    Last edited by taurus; September 20th 2007 at 03:47 AM.
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