Could someone help me with this integral? $\displaystyle \int\,x\sqrt{1+x}\,dx $
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According to the change of variables defined by $\displaystyle u=x+1$, the integral becomes to $\displaystyle \int x\sqrt{x+1}\,dx=\int(u-1)\sqrt u\,du$ Now you can take it from there.
Ah, okay. Thanks for helping.
You're welcome. -- Here on MHF we all have the predisposition to help, and when you post a question, it is answered quickly. Cheers, K.
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