# Thread: integral equation by Laplace transforms and contour integration

1. ## integral equation by Laplace transforms and contour integration

i have to solve $\int^t_0 f(\tau)sin(t - \tau) d\tau = \cos t - \cos 3t$ by using Laplace transforms and then inverting it using contour integration (which i'm incredibly vague on)
we were given the rule that if $f(t) = \int^t_0 g(t - \tau)h(\tau) d\tau$ then $F(s) = G(s)H(s)$, and also that the Laplace transform of an integral is $L[\int^t_0 f(\tau)d\tau] = \frac{1}{s}L[f(\tau)]$
i found the Laplace transform of $f(t) = \cos t$ is $F(s) = \frac{s}{s^2 + 1}$ and of $f(t) = \cos 3t$ is $F(s) = \frac{s}{s^2 + 9}$
do i have to Laplace transform the integral on the left as well? or do I multiply both Laplace transforms together and then integrate by contour integration?
i'm a little confused as to what to do next!

2. ## Re: integral equation by Laplace transforms and contour integration

Originally Posted by wik_chick88
i have to solve $\int^t_0 f(\tau)sin(t - \tau) d\tau = \cos t - \cos 3t$ by using Laplace transforms and then inverting it using contour integration (which i'm incredibly vague on)
we were given the rule that if $f(t) = \int^t_0 g(t - \tau)h(\tau) d\tau$ then $F(s) = G(s)H(s)$, and also that the Laplace transform of an integral is $L[\int^t_0 f(\tau)d\tau] = \frac{1}{s}L[f(\tau)]$
i found the Laplace transform of $f(t) = \cos t$ is $F(s) = \frac{s}{s^2 + 1}$ and of $f(t) = \cos 3t$ is $F(s) = \frac{s}{s^2 + 9}$
do i have to Laplace transform the integral on the left as well? or do I multiply both Laplace transforms together and then integrate by contour integration?
i'm a little confused as to what to do next!
Take the LT of your integal equaltion:

$\mathcal{L}\left[ \int^t_0 f(\tau)sin(t - \tau) d\tau = \cos t - \cos 3t\right]$

$\left[\mathcal{L} f (s)\right] \left[ \mathcal{L} \sin(s)\right] = \left[ \mathcal{L} \cos(s)\right]- \left[ \mathcal{L} h(s)\right]$

where $h(t)=\cos(3t)$

CB

3. ## Re: integral equation by Laplace transforms and contour integration

so am I solving for $f(t)$? ie. i find the Laplace transform of $sin(t - \tau)$ and sub that and also my Laplace transforms of $\cos t$ and $\cos 3t$ into the equation, simplify and then inverse Laplace transform to get $f(t)$?

Yes.

CB