Thread: Calculating an area limited by three functions

"An area is limited by the curve y1=(2/(x-1))-1, the curve y2=e^(-3x) and the line x=2.

Mark up the area in a coordinate system and calculate the area."

I'm pretty sure I should do some type of integration, but I'm having trouble finding a good way to start...

Have you drawn the graphs of the functions? It will give you more insight in the question I think.

Yeah, I did this in WA, didn't give me much though...

((2/(x+1))-1) e^(-3x) 2 - Wolfram|Alpha

Yeah, I did this in WA, didn't give me much though...

((2/(x+1))-1) e^(-3x) 2 - Wolfram|Alpha

the WA graphs you linked do not correspond do the equations you wrote in post #1.

1) youve ploted y=2 instead of x=2
2) you've plotted y1=(2/(x+1))-1

Decide which is the right set of graphs, then identify the vaklues of x which are in the region (one of the limits of x will be 2).

Then integrate both functions over those x values and subtract one from the other. Do you understand why this works?