# Thread: Calculating an area limited by three functions

1. ## Calculating an area limited by three functions

"An area is limited by the curve y1=(2/(x-1))-1, the curve y2=e^(-3x) and the line x=2.

Mark up the area in a coordinate system and calculate the area."

I'm pretty sure I should do some type of integration, but I'm having trouble finding a good way to start...

2. ## Re: Calculating an area limited by three functions

Have you drawn the graphs of the functions? It will give you more insight in the question I think.

3. ## Re: Calculating an area limited by three functions

Yeah, I did this in WA, didn't give me much though...

&#40;&#40;2&#47;&#40;x&#43;1&#41;&#41;-1&#41; e&#94;&#40;-3x&#41; 2 - Wolfram|Alpha

4. ## Re: Calculating an area limited by three functions

Yeah, I did this in WA, didn't give me much though...

&#40;&#40;2&#47;&#40;x&#43;1&#41;&#41;-1&#41; e&#94;&#40;-3x&#41; 2 - Wolfram|Alpha
the WA graphs you linked do not correspond do the equations you wrote in post #1.

1) youve ploted y=2 instead of x=2
2) you've plotted y1=(2/(x+1))-1

Decide which is the right set of graphs, then identify the vaklues of x which are in the region (one of the limits of x will be 2).

Then integrate both functions over those x values and subtract one from the other. Do you understand why this works?