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Math Help - frustrating indefinite integral

  1. #1
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    frustrating indefinite integral

    I need to integrate x^9\sqrt{x^5-3}
    I just cant seem to get the answer my calculator gives me and I could really use some help on this one!
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  2. #2
    Senior Member BAdhi's Avatar
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    Re: frustrating indefinite integral

    use the substitution - t=x^5 you'll end up getting \int \frac{t\sqrt{t-3}}{5}dt

    think you can carry on from here.
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  3. #3
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    Re: frustrating indefinite integral

    Quote Originally Posted by BAdhi View Post
    use the substitution - t=x^5 you'll end up getting \int \frac{t\sqrt{t-3}}{5}dt

    think you can carry on from here.
    With another substitution \displaystyle u = t - 3
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  4. #4
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    Re: frustrating indefinite integral

    why not just use one substitution s = x^5 - 3?
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  5. #5
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    Re: frustrating indefinite integral

    Quote Originally Posted by NeedDirection View Post
    I need to integrate x^9\sqrt{x^5-3}
    I just cant seem to get the answer my calculator gives me and I could really use some help on this one!
    Integration by parts with:

    u=x^5

    and

    dv=x^4 \sqrt{x^5-3}

    CB
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  6. #6
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    Re: frustrating indefinite integral

    Thanks guys, I finally got it worked out! I couldn't figure out the last way of doing it with integration by parts but oh well, whatever works!
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  7. #7
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    Re: frustrating indefinite integral

    Quote Originally Posted by NeedDirection View Post
    oh well, whatever works!
    Absolutely. But, the parts way is too neat not to have been the point of the puzzle. So, just in case a picture helps...



    ... where (key in spoiler) ...

    Spoiler:



    ... is the product rule, straight continuous lines differentiating downwards with respect to x.



    Then, for the other pic, we have also...



    ... the chain rule. Straight continuous lines differentiate downwards (integrate up) with respect to the main variable (in this case x), and the straight dashed line similarly but with respect to the dashed balloon expression (the inner function of the composite which is subject to the chain rule).

    (Wrapped inside the legs uncrossed version of the product rule.)



    Zooming in on the chain rule (and, to that end, un-crossing the legs of the product rule), and following through...



    Full size


    __________________________________________________ __________

    Don't integrate - balloontegrate!

    Balloon Calculus; standard integrals, derivatives and methods

    Balloon Calculus Drawing with LaTeX and Asymptote!
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  8. #8
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    Re: frustrating indefinite integral

    the integration by parts illustrates why the substitutions work: splitting x^9 into x^5 and x^4 gives you something outside the radical, which is the derivative (well, almost) of the beastie inside the radical. and this is good, because as any conservative will tell you, radicals are evil, and need to be monitored closely.
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