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Math Help - Limits/Derivatives (have to go to class soon)

  1. #1
    Member FalconPUNCH!'s Avatar
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    Limits/Derivatives (have to go to class soon)

    I tried this several times but couldn't get it right. I do not want answers to this. I just need help on how to set it up.

    The point P(1,1/2) lies on the curve y = x/(1+x).
    [A] If Q is the point (x, x/(1+x)), find the slope of the secant line PQ with the following vaules of x:
    1) .5 2).9 3).99 4).999
    I just don't know how to set the equation up. Please help as soon as possible. Thank you
    Last edited by FalconPUNCH!; September 18th 2007 at 06:17 AM.
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  2. #2
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by FalconPUNCH! View Post
    I tried this several times but couldn't get it right. I do not want answers to this. I just need help on how to set it up.

    I just don't know how to set the equation up. Please help as soon as possible. Thank you
    Well, you are simply trying to find the slope between the two points, so
    \text{slope} = \frac{\frac{x}{1 + x} - \frac{1}{2}}{x - 1}

    Now just plug in your x values.

    -Dan
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  3. #3
    Member FalconPUNCH!'s Avatar
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    Quote Originally Posted by topsquark View Post
    Well, you are simply trying to find the slope between the two points, so
    \text{slope} = \frac{\frac{x}{1 + x} - \frac{1}{2}}{x - 1}

    Now just plug in your x values.

    -Dan
    I did that but when I looked in the back to check if my answers were correct they differed from what I got when i plugged in the values into that equation.

    Edit: I see what I did wrong. thank you a lot.
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