End Point Maxima and Minima?
Quick question, in my Calc class we are covering End Point Maxima and Minima.
I understand that for lets say prove there is a max at x=-2
f(x)=(x+2)^(3/2)+5*x^2 for x >= -2
You can just plug in -2 and get -20, which proves that it is a max because the function is decreasing to the right of it.
What I do not understand is this
f(x)=(25-x^2)^(1/2)-2*x^2 for -5 <= x <= 5
It is asking if 5 is a max or a min
But when you plug in 5 it DNE
The book describes using infinity, but I do not understand how they are using it?
Thanks for anyone who can offer any help!
Re: End Point Maxima and Minima?
note that is defined at , but is not.
for , ... is increasing on that interval. therefore, is an endpoint minimum.
for , ... is decreasing on that interval. therefore, is an endpoint minimum.
is a maximum