The graph of the bounded region is rectangle. It has a length of 40, and width of 10.

A = L * W

A = 40 * 10

A = 400.

Results 1 to 5 of 5

- October 22nd 2011, 10:49 PM #1

- Joined
- Feb 2010
- Posts
- 460
- Thanks
- 34

- October 23rd 2011, 05:57 AM #2

- October 23rd 2011, 07:41 AM #3

- Joined
- Feb 2010
- Posts
- 460
- Thanks
- 34

- October 23rd 2011, 09:07 AM #4

- Joined
- Apr 2005
- Posts
- 17,411
- Thanks
- 2187

## Re: area4

If you add and subtract you get . Let u= x+y and v= y. x= u- y= u- v so the equation becomes .

For x= u- v>0, |x|= |u-v|= u- v so that becomes . Complete the square by adding 400 and subtracting 400 on the left: . That is a hyperbola, in the uv-plane, with center at (-20, -20), vertices (0, -20) and (-40, -20), and vertical asymptotes at 45 degree angles to the axes. That is, one of the asymptotes**is**the line u= v and, since we require that u- v> 0 here, we have only the branch of the hyperbola on that side.

If u- v< 0, then |u- v|= v- u> 0 and the equation becomes and, after completing the square, , a hyperbola with center at (20, 20), vertices (0, 20) and (40, 20), and u= v and u= -v as asymptotes again. Since u< v now, we have the branch of the hyperbola now on the opposite side. Those don't cross: one lies on one side of v= u and the other on the opposite side, so I don't see how they can create a bounded region!

- October 24th 2011, 12:38 AM #5