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Math Help - area integral problem

  1. #1
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    area integral problem

    Hi everyone,

    Can somone tell me if this is correct, please?

    I'm trying to find the area under the curves x=ysquared-4y and x=2y-ysquared

    I took 2y-y^2 -y^2-4ydy from -3 to 0.

    I got 62/2

    Thank you very much
    Last edited by chocolatelover; September 17th 2007 at 08:23 PM.
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by chocolatelover View Post
    Hi everyone,

    Can somone tell me if this is correct, please?

    I'm trying to find the area under the curves x=ysquared-4y and x=2y-ysquared

    I took 2y-y^2 -y^2-4ydy from -3 to 0.

    I got 62/2

    Thank you very much
    Area under or between?

    The two curves intersect where y^2-4y=2y-y^2, to me the
    points of intersection appear to be y=0,\ y=3, so you want:

    <br />
\int_0^3 (2y-y^2)-(y^2-4y)\ dy = \int_0^3 6y-2y^2\ dy <br />

    RonL
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  3. #3
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    Thank you very much

    I got 9 as my final answer. Does that look right?

    Thank you
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  4. #4
    Senior Member
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    Quote Originally Posted by chocolatelover View Post
    Thank you very much

    I got 9 as my final answer. Does that look right?

    Thank you
    Yes, this is correct.
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