i want to find and sketch the domain of
f(x,y) = 1/[(x+y²)(2-x)]^½
so what I did
2-x > 0, thus x <2
x+y² > 0, so x > -y²
that right?
Yeah, all I wanted to do was point out that the product of two numbers can be positive if both of the multiplicands are negative. I hadn't gotten so far as to determine if there actually were any numbers in the set or not. So the answer is, I wasn't thinking as deeply as was necessary!