Have you considered the logarithm?
I need know how to show the work on this limit problem. I have been to several school tutors who can't seem to do it correctly. What is the limit as x approaches 0 from the right of x^(2/x)? The question as you would type it into an Computer Algebra System is: limit(x^(2/x),x,0,1)
This gives us 0 which is the correct answer but I have no idea how to show the work. I know that in the end it someone should be e^(-∞) which equals 0. Someone please help!
Yeah I got there. It makes sense now. I guess it ends up being -∞ because 2ln(.0000000000...1) is a large negative number over a very very small number. Thank you for the reminder. I made the mistake of trying to use L'Hospitals rule since that was the chapter this questions was in :/.
Thanks!