Normalizatoin Constant and a Gaussian Integral.

Hello! I'm attempting to compute the normalization constant N for the following function $\displaystyle f(x)=N e^{-(x-x_0)/2k^{2})}$. This is generally done by evaluating $\displaystyle \int |f(x)|^{2}dx=1$, where the limits of integration are -inf to +inf.

I can get this right up until the point where I need to make a u substitution.

$\displaystyle 1=\int |N e^{-(x-x_0)/2k^{2})}|^{2}dx$

$\displaystyle 1=\int N^2 e^{-(x-x_0)^2/k^2} dx$

$\displaystyle 1=N^2 \int e^{-(x-x_0)^2/k^2} dx$

making the substitution $\displaystyle u=x-x_0, du=dx$

$\displaystyle 1=N^2 \int e^{-u^2/k^2}du$

This integral is only slightly more clear to me. It looks like a Gaussian integral, but, how do I go about solving it? Any help is much appreciated.

Re: Normalizatoin Constant and a Gaussian Integral.

I would actually make the subtitution

$\displaystyle u=\frac{x-x_{0}}{k}.$

That should make the integral a more standard integral.

Re: Normalizatoin Constant and a Gaussian Integral.

So, that would yield: $\displaystyle 1=N^{2} \int e^{-u^{2}}du=N^{2}\sqrt{\pi}$ ?

Re: Normalizatoin Constant and a Gaussian Integral.

Quote:

Originally Posted by

**atomicpedals** So, that would yield: $\displaystyle 1=N^{2} \int e^{-u^{2}}du=N^{2}\sqrt{\pi}$ ?

I don't think you've quite got it yet. The substitution I suggested requires a change in the differential as well. The final answer had better have a 'k' in it somewhere.

Re: Normalizatoin Constant and a Gaussian Integral.

Woops! $\displaystyle 1=N^{2}\frac{\sqrt{\pi}}{k}$ which then yeilds a normalization constant $\displaystyle N=\pm\frac{\sqrt{k}}{\pi^{1/4}}$ .

Re: Normalizatoin Constant and a Gaussian Integral.

Better, but still not quite there yet. Be careful as to numerator and denominator. Can you show your working, please?

Re: Normalizatoin Constant and a Gaussian Integral.

So my line of thinking was as follows:

$\displaystyle u=\frac{(x-x_{0})}{k}$ which I think yields $\displaystyle du=\frac{1}{k}dx$ and so $\displaystyle 1=N^{2}\int \frac{1}{k}e^{-u^{2}}du=1=N^{2}\frac{1}{k}\int e^{-u^{2}}du=N^{2}\frac{1}{k}\sqrt{\pi}$

Re: Normalizatoin Constant and a Gaussian Integral.

Wait... I should have $\displaystyle kdu=dx$ shouldn't I...

Re: Normalizatoin Constant and a Gaussian Integral.

Quote:

Originally Posted by

**atomicpedals** So my line of thinking was as follows:

$\displaystyle u=\frac{(x-x_{0})}{k}$ which I think yields $\displaystyle du=\frac{1}{k}dx$

Fine so far.

Quote:

and so $\displaystyle 1=N^{2}\int \frac{1}{k}e^{-u^{2}}du$

The problem here is that what you start with is a dx, not a du. Solve du = dx/k for dx. That's what you must plug in.

Quote:

$\displaystyle =1=N^{2}\frac{1}{k}\int e^{-u^{2}}du=N^{2}\frac{1}{k}\sqrt{\pi}$