dy/dx = 0? Why would that help you find a VERTICAL asymptote? Try dx/dy.
Well, it's not so much the differentiating I need help with. we have this (2x-x^2y^2=4y-4) formula, and need to use implicit differentiation to find the leftmost point of the graph. figured out that dy/dx = (1-xy^2)/(2-x^2y), guessing I need solve it equal to 0.
Tried solving dy/dx = 0, got y=+/- sqrt(x-1) and tried substituting it into the original formula but that was incorrect. I'm stuck!
What's the difference? Anyway, one should also be sure of two other things, besides dx/dy = 0:
1) dy/dx is not also zero, and
2) dx/dy doesn't have some other value as well as zero.
We are looking for a left-most point.