Originally Posted by
stargazer00 ok, so this is how i went about this:
using f'(g(x)) * g'(x)
y= (x^2)e^(-1/x)
f(x) = x^2
f'(x) = 2x
g(x) = e^-1/x
g'(x) = (-1/x)e^(-1/2-1)
2(e^(-1/x)) *1/2e^((-1/x)-1) what is this? do you know how to take the derivative of an exponential function?
now what?