# Thread: Epsilon delta definition of limit.

1. ## Epsilon delta definition of limit.

Q1) The precise definition of lim x->a (f(x)≠L) is as follows

There exists an ε>0 such that for every δ>0 and if 0<|x-a|<δ then |f(x)-L|>ε

Show that lim x->0 sin(pi/x)≠L

note: Take L=0.19

Q2) Calculate lim x->1 (sqrt(x+8)) and prove it by using ε and δ definition of limit.

2. ## Re: Plz help me about epsilon delta definition of limit.

Welcome to MHF.

Show us what you have tried.

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3. ## Re: Plz help me about epsilon delta definition of limit.

Thank you!
about Q2 I find 0<|x-1|<δ and |sqrt(x+8)-3|<ε and |(sqrt(x+8)-3)*(sqrt(x+8)+3)/(sqrt(x+8)+3)|<ε equals |(x-1)/(sqrt(x+8)+3)|<ε Am I right

But about Q1 I can not find anything.

4. ## Re: Plz help me about epsilon delta definition of limit.

Q2: That's a good beginning, to write it more formal, we have to show that:
$\forall \epsilon>0, \exist \delta>0, \forall x \in \ \mbox{dom f}: 0<|x-1|<\delta \Rightarrow |\sqrt{x+8}-3|<\epsilon$
Proof:
$|\sqrt{x+8}-3|<\epsilon \Rightarrow \left|\frac{(\sqrt{x+8}-3)(\sqrt{x+8}+3)}{\sqrt{x+8}+3}\right|\Rightarrow \left|\frac{x-1}{\sqrt{x+8}+3}\right| \Rightarrow \frac{|x-1|}{|\sqrt{x+8}+3|}<\epsilon$
Now, suppose $\delta=1$ therefore $|x-1|<1 \Leftrightarrow -1 ... go further with this given to find for each $\epsilon$ a corresponding $\delta$

6. ## Re: Epsilon delta definition of limit.

Originally Posted by mervecetin
Q1) The precise definition of lim x->a (f(x)≠L) is as follows

There exists an ε>0 such that for every δ>0 and if 0<|x-a|<δ then |f(x)-L|>ε

Show that lim x->0 sin(pi/x)≠L

note: Take L=0.19
For Q1:

Start by inserting the given quantities, in this case L, a, and f(x), into the precise definition for the limit not existing.