Epsilon delta definition of limit.

Q1) The precise definition of lim x->a (f(x)≠L) is as follows

There exists an ε>0 such that for every δ>0 and if 0<|x-a|<δ then |f(x)-L|>ε

Show that lim x->0 sin(pi/x)≠L

note: Take L=0.19

Q2) Calculate lim x->1 (sqrt(x+8)) and prove it by using ε and δ definition of limit.

Re: Plz help me about epsilon delta definition of limit.

Welcome to MHF.

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Re: Plz help me about epsilon delta definition of limit.

Thank you!

about Q2 I find 0<|x-1|<δ and |sqrt(x+8)-3|<ε and |(sqrt(x+8)-3)*(sqrt(x+8)+3)/(sqrt(x+8)+3)|<ε equals |(x-1)/(sqrt(x+8)+3)|<ε Am I right

But about Q1 I can not find anything.

Re: Plz help me about epsilon delta definition of limit.

Q2: That's a good beginning, to write it more formal, we have to show that:

$\displaystyle \forall \epsilon>0, \exist \delta>0, \forall x \in \ \mbox{dom f}: 0<|x-1|<\delta \Rightarrow |\sqrt{x+8}-3|<\epsilon$

Proof:

$\displaystyle |\sqrt{x+8}-3|<\epsilon \Rightarrow \left|\frac{(\sqrt{x+8}-3)(\sqrt{x+8}+3)}{\sqrt{x+8}+3}\right|\Rightarrow \left|\frac{x-1}{\sqrt{x+8}+3}\right| \Rightarrow \frac{|x-1|}{|\sqrt{x+8}+3|}<\epsilon$

Now, suppose $\displaystyle \delta=1$ therefore $\displaystyle |x-1|<1 \Leftrightarrow -1<x-1<1 \Leftrightarrow 0<x<2$ ... go further with this given to find for each $\displaystyle \epsilon$ a corresponding $\displaystyle \delta$

Re: Epsilon delta definition of limit.

Thank you. What about Q3?

Re: Epsilon delta definition of limit.

Quote:

Originally Posted by

**mervecetin** Q1) The precise definition of lim x->a (f(x)≠L) is as follows

There exists an ε>0 such that for every δ>0 and if 0<|x-a|<δ then |f(x)-L|>ε

Show that lim x->0 sin(pi/x)≠L

note: Take L=0.19

For Q1:

Start by inserting the given quantities, in this case L, a, and f(x), into the precise definition for the limit not existing.

Please, show us something.