I am trying to set up and evaluate the definite integral that gives the area of the region bounded by the graph of the function and the tangent line to the graph at the point ( -1, 1)
Now, i am aware this is an area problem so i probably have
would g(x) = x ^3 -2x ?
for the tangent line would it be in the form y = mx + b?
How would i find that? I have graphed the x ^3 -2x and made the point ( -1, 1) and can see the region for the area.
Would i need to take the dirivitive of x ^3 -2x and plug in -1 for x?