# Thread: derivatives

1. ## derivatives

Can anyone help me find the derivative of 3xe^-kx
-thank you

2. ## Re: derivatives

use chain rule, $u=3x$ and $v=e^{-kx}$

3. ## Re: derivatives

don't you have to use a combination of the product rule and chain rule?

4. ## Re: derivatives

Originally Posted by consevans
Can anyone help me find the derivative of 3xe^-kx
If $y=f(x)e^{g(x)}$ then $y'=f'(x)e^{g(x)}+f(x)g'(x)e^{g(x)}$

5. ## Re: derivatives

Originally Posted by BAdhi
use chain rule, $u=3x$ and $v=e^{-kx}$
I think you mean "product rule".