# derivatives

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• Oct 19th 2011, 06:16 AM
consevans
derivatives
Can anyone help me find the derivative of 3xe^-kx
-thank you
• Oct 19th 2011, 06:28 AM
BAdhi
Re: derivatives
use chain rule, $u=3x$ and $v=e^{-kx}$
• Oct 19th 2011, 07:14 AM
consevans
Re: derivatives
don't you have to use a combination of the product rule and chain rule?
• Oct 19th 2011, 07:25 AM
Plato
Re: derivatives
Quote:

Originally Posted by consevans
Can anyone help me find the derivative of 3xe^-kx

If $y=f(x)e^{g(x)}$ then $y'=f'(x)e^{g(x)}+f(x)g'(x)e^{g(x)}$
• Oct 19th 2011, 09:41 AM
HallsofIvy
Re: derivatives
Quote:

Originally Posted by BAdhi
use chain rule, $u=3x$ and $v=e^{-kx}$

I think you mean "product rule".