I got a question:
Find dy/dx of:
Now what i got is:
((-3x^2)-2) / (3y^2)
By doing this:
what am i doing wrong?
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It looks right, I think you just messed up the negative signs at the end a bit.
and this one:
((x^2)/4) + ((y^2)/16) = 1
i did this:
((8x-(x^2))/16) + ((32y-(y^2))/256 dy/dx
Now from here am confused if its right?
Originally Posted by taurus ((x^2)/4) + ((y^2)/16) = 1 To derive this, you gotta use the Implicit Differentiation.
Since we want , we use the chain rule for , this yields
Now just make the subject of the equation.
that doesnt yield the correct answer? could you run through the steps pls
Last edited by taurus; Sep 17th 2007 at 11:22 AM.
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