I got a question:

Find dy/dx of:

(x^3)+(y^3)-(2x)=3

Now what i got is:

((-3x^2)-2) / (3y^2)

By doing this:

(3x^2)+(3y^2)dy/dx-2=0

what am i doing wrong?

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- Sep 17th 2007, 06:16 AM #1

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- Sep 17th 2007, 06:25 AM #2

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- Sep 17th 2007, 07:44 AM #5

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