Evaluate the integral. ((e^2x))/((4+e^4x)) I think u=e^2x du=2e^2x Am I doing this right.
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Originally Posted by homeylova223 Evaluate the integral. ((e^2x))/((4+e^4x)) I think u=e^2x du=2e^2x Am I doing this right. consider the antiderivative of $\displaystyle \frac{u'}{1 + u^2}$ ... arctangent?
Yes that does seem like arc tan.
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