Inverse trigonometric functions?

Evaluate the integral.

((e^2x))/((4+e^4x))

I think u=e^2x du=2e^2x

Am I doing this right.

Quote:

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Originally Posted by homeylova223

Evaluate the integral.

((e^2x))/((4+e^4x))

I think u=e^2x du=2e^2x

Am I doing this right.

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consider the antiderivative of

... arctangent?

Yes that does seem like arc tan.