Evaluate the integral.

((e^2x))/((4+e^4x))

I think u=e^2x du=2e^2x

Am I doing this right.

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- Oct 18th 2011, 04:05 PMhomeylova223Inverse trigonometric functions?
Evaluate the integral.

((e^2x))/((4+e^4x))

I think u=e^2x du=2e^2x

Am I doing this right. - Oct 18th 2011, 04:07 PMskeeterRe: Inverse trigonometric functions?
- Oct 18th 2011, 04:08 PMhomeylova223Re: Inverse trigonometric functions?
Yes that does seem like arc tan.