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Math Help - tan of pi/2

  1. #1
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    tan of pi/2

    I have done integration and I get a function tan u and a limit pi/2. What value can I call this?
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  2. #2
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    Re: tan of pi/2

    Is that complex infinity? maybe

    cause its i(e^(-iu)-e^(iu))/(e^(iu)+e^(-iu))
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  3. #3
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    Re: tan of pi/2

    I think it can be done using a notation that says something like epsilon tends to 0.
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  4. #4
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    Re: tan of pi/2

    Quote Originally Posted by Stuck Man View Post
    I have done integration and I get a function tan u and a limit pi/2. What value can I call this?
    \displaystyle \lim_{u\to \frac{\pi}{2}}\tan u does not exist.
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  5. #5
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    Re: tan of pi/2

    What then is the method for finding an area up to pi/2 under a tangent graph? Wolfram alpha gives a value the same as my graphing software but not any steps.
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  6. #6
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    Re: tan of pi/2

    Quote Originally Posted by Stuck Man View Post
    What then is the method for finding an area up to pi/2 under a tangent graph? Wolfram alpha gives a value the same as my graphing software but not any steps.
    \int^\frac{\pi}{2}_0\tan x=[\ln \sec x]_0^{\frac{\pi}{2}}\to\infty
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  7. #7
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    Re: tan of pi/2

    I meant to say I have tan x in the square brackets and a limit of pi/2.
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  8. #8
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    Re: tan of pi/2

    Quote Originally Posted by Stuck Man View Post
    I meant to say I have tan x in the square brackets and a limit of pi/2.
    I answered that in post #4.

    How about posting the whole problem?
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  9. #9
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    Re: tan of pi/2

    Find the area in [0.5,1] under graph (1-x) / (1-x^2)^0.5 to the x-axis. I think its 0.181.
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  10. #10
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    Re: tan of pi/2

    Quote Originally Posted by Stuck Man View Post
    Find the area in [0.5,1] under graph (1-x) / (1-x^2)^0.5 to the x-axis. I think its 0.181.
    Agreed.

    What does this have to do with \displaystyle \lim_{u\to\frac{\pi}{2}}\tan u though?
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  11. #11
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    Re: tan of pi/2

    I have found a mistake in my work and its quite different now.
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