1. ## tan of pi/2

I have done integration and I get a function tan u and a limit pi/2. What value can I call this?

2. ## Re: tan of pi/2

Is that complex infinity? maybe

cause its i(e^(-iu)-e^(iu))/(e^(iu)+e^(-iu))

3. ## Re: tan of pi/2

I think it can be done using a notation that says something like epsilon tends to 0.

4. ## Re: tan of pi/2

Originally Posted by Stuck Man
I have done integration and I get a function tan u and a limit pi/2. What value can I call this?
$\displaystyle \lim_{u\to \frac{\pi}{2}}\tan u$ does not exist.

5. ## Re: tan of pi/2

What then is the method for finding an area up to pi/2 under a tangent graph? Wolfram alpha gives a value the same as my graphing software but not any steps.

6. ## Re: tan of pi/2

Originally Posted by Stuck Man
What then is the method for finding an area up to pi/2 under a tangent graph? Wolfram alpha gives a value the same as my graphing software but not any steps.
$\int^\frac{\pi}{2}_0\tan x=[\ln \sec x]_0^{\frac{\pi}{2}}\to\infty$

7. ## Re: tan of pi/2

I meant to say I have tan x in the square brackets and a limit of pi/2.

8. ## Re: tan of pi/2

Originally Posted by Stuck Man
I meant to say I have tan x in the square brackets and a limit of pi/2.
I answered that in post #4.

How about posting the whole problem?

9. ## Re: tan of pi/2

Find the area in [0.5,1] under graph (1-x) / (1-x^2)^0.5 to the x-axis. I think its 0.181.

10. ## Re: tan of pi/2

Originally Posted by Stuck Man
Find the area in [0.5,1] under graph (1-x) / (1-x^2)^0.5 to the x-axis. I think its 0.181.
Agreed.

What does this have to do with $\displaystyle \lim_{u\to\frac{\pi}{2}}\tan u$ though?

11. ## Re: tan of pi/2

I have found a mistake in my work and its quite different now.