# Math Help - Centripetal Force

1. ## Centripetal Force

A body of mass 5 kg moves in a counterclockwise circular path of radius 10 meters in the xy-plane, making one revolution every 7 seconds. At the time t=0, the body is at the rightmost point of the circle.

r(t)= 10cos(2pi(t)/7i+10sin(2pi(t)/7

Now my a(t)=r''(t) vector comes out to be:
-40pi^2/49cos(2pi(t)/7)i-40pi^2/49sin(2pi(t)/7)

Is this right?

2. ## Re: Centripetal Force

correct as I see it.

3. ## Re: Centripetal Force

so the centripetal force is 5*[ -40pi^2/49cos(2pi(t)/7)i-40pi^2/49sin(2pi(t)/7) ]?

4. ## Re: Centripetal Force

Originally Posted by Bracketology
so the centripetal force is 5*[ -40pi^2/49cos(2pi(t)/7)i-40pi^2/49sin(2pi(t)/7) ]?
yes, Newton's second law of motion ... $F_c = ma_c$

Thanks!